Prerequisite:-
Dynamic programming
Solution:-
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| #include<bits/stdc++.h> | |
| using namespace std; | |
| long long ans(long long n,vector<long long>&dp){ | |
| if(n==0) | |
| return 0; | |
| if(dp[n]) | |
| return dp[n]; | |
| return dp[n]=max(n,ans(n/2,dp)+ans(n/3,dp)+ans(n/4,dp)); | |
| } | |
| int main(){ | |
| long long n; | |
| while(scanf("%lld",&n)!=EOF){ | |
| //cin>>n; | |
| //cout<<"n= "<<n<<endl; | |
| vector<long long>dp(n+1,0); | |
| cout<<ans(n,dp)<<endl; | |
| } | |
| return 0; | |
| } |
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